10=3x^2+16x+15

Solution for 10=3x^2+16x+15 equation:

10=3x^2+16x+15

We move all terms to the left:

10-(3x^2+16x+15)=0

We get rid of parentheses

-3x^2-16x-15+10=0

We add all the numbers together, and all the variables

-3x^2-16x-5=0

a = -3; b = -16; c = -5;
Δ = b2-4ac
Δ = -162-4·(-3)·(-5)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-14}{2*-3}=\frac{2}{-6}
=-1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+14}{2*-3}=\frac{30}{-6}
=-5
$